Team:DTU-Denmark/Design test

From 2011.igem.org

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<html>
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{{:Team:DTU-Denmark/Templates/Standard_page_begin_no_heading}}
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<style type="text/css">
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/*
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root element for the scrollable.
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when scrolling occurs this element stays still.
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*/
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.scrollable {
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/* required settings */
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{{:Team:DTU-Denmark/Templates/Take_the_tour_slider}}
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position:relative;
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overflow:hidden;
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width: 660px;
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height:90px;
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}
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/*
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<html>
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root element for scrollable items. Must be absolutely positioned
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<script type="text/javascript">
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and it should have a extremely large width to accommodate scrollable items.
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    $( '#header' ).scrollFollow();
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it's enough that you set width and height for the root element and
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</script>
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not for this element.
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<script type="text/javascript">
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*/
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    $( '#navigation' ).scrollFollow();
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.scrollable .items {
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</script>
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/* this cannot be too large */
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<script type="text/javascript">
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width:20000em;
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    $( '.centering' ).scrollFollow();
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position:absolute;
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</script>
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}
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<script type="text/javascript">
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    $( '.slider' ).scrollFollow();
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/*
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a single item. must be floated in horizontal scrolling.
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typically, this element is the one that *you* will style
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the most.
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*/
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.items div {
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float:left;
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}
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</style>
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<script>
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// execute your scripts when the DOM is ready. this is mostly a good habit
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$(function() {
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// initialize scrollable
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$(".scrollable").scrollable();
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});
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</script>
</script>
</html>
</html>
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{{:Team:DTU-Denmark/Templates/Use_latex}}
 
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{{:Team:DTU-Denmark/Templates/Use_jquerytools}}
 
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{{:Team:DTU-Denmark/Templates/Standard_page_begin|This is the page name}}
 
Math: When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
Math: When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
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<html>
 
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<!-- "previous page" action -->
 
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<a class="prev browse left"></a>
 
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<!-- root element for scrollable -->
 
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<div class="scrollable"> 
 
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  <!-- root element for the items -->
 
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  <div class="items">
 
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      <!-- 1-5 -->
 
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      <div>
 
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        <img src="http://farm1.static.flickr.com/143/321464099_a7cfcb95cf_t.jpg" />
 
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        <img src="http://farm4.static.flickr.com/3089/2796719087_c3ee89a730_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/79/244441862_08ec9b6b49_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/28/66523124_b468cf4978_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/164/399223606_b875ddf797_t.jpg" />
 
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      </div>
 
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      <!-- 5-10 -->
 
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      <div>
 
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        <img src="http://farm1.static.flickr.com/163/399223609_db47d35b7c_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/135/321464104_c010dbf34c_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/40/117346184_9760f3aabc_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/153/399232237_6928a527c1_t.jpg" />
 
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        <img src="http://farm1.static.flickr.com/50/117346182_1fded507fa_t.jpg" />
 
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      </div>
 
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      <!-- 10-15 -->
 
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      <div>
 
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        <img src="http://farm4.static.flickr.com/3629/3323896446_3b87a8bf75_t.jpg" />
 
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        <img src="http://farm4.static.flickr.com/3023/3323897466_e61624f6de_t.jpg" />
 
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        <img src="http://farm4.static.flickr.com/3650/3323058611_d35c894fab_t.jpg" />
 
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        <img src="http://farm4.static.flickr.com/3635/3323893254_3183671257_t.jpg" />
 
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        <img src="http://farm4.static.flickr.com/3624/3323893148_8318838fbd_t.jpg" />
 
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      </div>
 
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  </div>
 
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</div>
 
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<!-- "next page" action -->
 
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<a class="next browse right"></a>
 
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</html>
 
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Latest revision as of 13:50, 5 September 2011





Math: When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

Lorem ipsum dolor sit amet, consectetuer adipiscing elit, sed diam nonummy nibh euismod tincidunt ut laoreet dolore magna aliquam erat volutpat. Ut wisi enim ad minim veniam, quis nostrud exerci tation ullamcorper suscipit lobortis nisl ut aliquip ex ea commodo consequat. Duis autem vel eum iriure dolor in hendrerit in vulputate velit esse molestie consequat, vel illum dolore eu feugiat nulla facilisis at vero eros et accumsan et iusto odio dignissim qui blandit praesent luptatum zzril delenit augue duis dolore te feugait nulla facilisi. Nam liber tempor cum soluta nobis eleifend option congue nihil imperdiet doming id quod mazim placerat facer possim assum.

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Opdeling:

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Contents

Heading level 2

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Heading level 3

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Heading level 4

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Heading level 5

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Heading level 6

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Endnu en level 2 heading

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