User talk:Yazbo91
From 2011.igem.org
(Difference between revisions)
Line 5: | Line 5: | ||
* When you define steady state as meaning 99% of the cellulose is used up, it becomes unclear what it means for cellobiose or glucose. | * When you define steady state as meaning 99% of the cellulose is used up, it becomes unclear what it means for cellobiose or glucose. | ||
* You say Figure 3 shows cellobiose doesn't reach a steady state. But it goes to zero. If you mean it goes negative, you'll have to replot the graph to show that... | * You say Figure 3 shows cellobiose doesn't reach a steady state. But it goes to zero. If you mean it goes negative, you'll have to replot the graph to show that... | ||
- | * You say "Analysing steady state is important to find out whether a system accumulates excess mass or energy" - but we know it can't in reality, right, since this violates physics? | + | * You say "Analysing steady state is important to find out whether a system accumulates excess mass or energy" - but we know it can't in reality, right, since this violates physics? Do you mean analysing steady state is important as a way of testing if the model is sane? |
[[User:Allancrossman|Allancrossman]] 16:38, 9 September 2011 (CDT) | [[User:Allancrossman|Allancrossman]] 16:38, 9 September 2011 (CDT) |
Revision as of 21:44, 9 September 2011
Oh hai.
Some comments:
- When you define steady state as meaning 99% of the cellulose is used up, it becomes unclear what it means for cellobiose or glucose.
- You say Figure 3 shows cellobiose doesn't reach a steady state. But it goes to zero. If you mean it goes negative, you'll have to replot the graph to show that...
- You say "Analysing steady state is important to find out whether a system accumulates excess mass or energy" - but we know it can't in reality, right, since this violates physics? Do you mean analysing steady state is important as a way of testing if the model is sane?
Allancrossman 16:38, 9 September 2011 (CDT)